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0=4x^2+7x-7
We move all terms to the left:
0-(4x^2+7x-7)=0
We add all the numbers together, and all the variables
-(4x^2+7x-7)=0
We get rid of parentheses
-4x^2-7x+7=0
a = -4; b = -7; c = +7;
Δ = b2-4ac
Δ = -72-4·(-4)·7
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{161}}{2*-4}=\frac{7-\sqrt{161}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{161}}{2*-4}=\frac{7+\sqrt{161}}{-8} $
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